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Last Modified: 1:01pm 10 Aug 11
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Last Modified: 1:01pm 10 Aug 11
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If a constant force F pushes an object in the same direction as the object moves, for a distance d, then the work done by the force on the object is simple:
work = F times d
But real life is rarely so simple. You need to know how to deal with more complicated situations.
The need for "the-component-of-force-in-the-same-direction-as-motion" occurs so frequently that physicists have a special shorthand notation to describe it: the dot product. (10 min)
But what if the direction of the force, or the object, CHANGES as the object moves?
Michael Richmond's version
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Last Modified: 1:01pm 10 Aug 11
|
Profile >> |
|
Research Interests: Nanoimaging | |
If a constant force F pushes an object in the same direction as the object moves, for a distance d, then the work done by the force on the object is simple:
work = F times d
But real life is rarely so simple. You need to know how to deal with more complicated situations.
The need for "the-component-of-force-in-the-same-direction-as-motion" occurs so frequently that physicists have a special shorthand notation to describe it: the dot product. (10 min)
But what if the direction of the force, or the object, CHANGES as the object moves?
Michael Richmond's version
|
|
Last Modified: 1:01pm 10 Aug 11
|
|
Profile >> |
If a constant force F pushes an object in the same direction as the object moves, for a distance d, then the work done by the force on the object is simple:
work = F times d
But real life is rarely so simple. You need to know how to deal with more complicated situations.
The need for "the-component-of-force-in-the-same-direction-as-motion" occurs so frequently that physicists have a special shorthand notation to describe it: the dot product. (10 min)
But what if the direction of the force, or the object, CHANGES as the object moves?
Michael Richmond's version
|
|
Last Modified: 1:01pm 10 Aug 11
|
|
Profile >> |
|
Research Interests: Nanoimaging | |