Consider two satellites in orbit around the Earth:
A is very close, B is far away.
satellite A feels a strong gravitational force, so it has
a large acceleration and a large speed
satellite B feels a weaker gravitational force, so it has
a small acceleration and a small speed
satellite A is close to the Earth, so the circumference of its
orbit is relatively small
satellite B is far to the Earth, so the circumference of its
orbit is relatively large
The result is that satellite A travels a small distance
with a high speed,
but satellite B must cover a larger distance
while moving at a lower speed.
The periods of the two satellites must be very different.
For example, consider
the International Space Station, which has an altitude
of about 360 km.
What is the distance between ISS and the center of the Earth?
What is the acceleration of the ISS in its orbit?
(Hint: use law of gravity)
What is the velocity of the ISS in its orbit?
(Hint: use centripetal acceleration formula)
How long does it take ISS to complete one orbit around the Earth?
Optional: Which way does ISS appear to move across the sky?
If you can see it when it is just above
above your local horizon,
estimate how long it will take to cross the sky.
(Hint: draw a big picture)
This means that if we stand on the ground and look up at night,
we occasionally see the ISS fly across the sky.
If the ISS carried TV transmission equipment, our satellite TV dishes
would have to track its motion across the sky;
that's hard.
Even worse, we wouldn't be able to see it most of the time.
No TV?! Argh!
So, to prevent this catastrophe, kindly network executives have
placed special satellites in orbits which have larger radii
than that of ISS. That means that they move more slowly,
AND they have to cover a larger distance.
Their orbital periods are much longer ....
exactly 24 hours.
We call these "geosynchronous" satellites, because they always
appear above the same spot on Earth.
Another way to put it is that they always appear
in the same spot in our sky.
If you point a satellite dish at one today, it will still
be looking at the right spot tomorrow -- and the next day --
and the next day -- and so on.
What is the period of a geosynchronous satellite, in seconds?
Write an equation which relates the period of a satellite's orbit
to its orbital radius r and speed v
Write another equation which describes the centripetal acceleration
of a satellite (v-squared over r) in terms
of capital G and the mass of the Earth
Put those two equations together to solve for the
special radius r of an orbit which has a period
of exactly 24 hours
Optional: What would the radius of a luna-synchronous
satellite orbit be?
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